15x^2-(12x)=48

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Solution for 15x^2-(12x)=48 equation:



15x^2-(12x)=48
We move all terms to the left:
15x^2-(12x)-(48)=0
a = 15; b = -12; c = -48;
Δ = b2-4ac
Δ = -122-4·15·(-48)
Δ = 3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3024}=\sqrt{144*21}=\sqrt{144}*\sqrt{21}=12\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{21}}{2*15}=\frac{12-12\sqrt{21}}{30} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{21}}{2*15}=\frac{12+12\sqrt{21}}{30} $

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